pd.Series.replace

pandas.Series.replace(to_replace=None, value=None, inplace=False, limit=None, regex=False, method='pad')

Supported Arguments

argument	datatypes	other requirements
to_replace	Scalar List of Scalars Dictionary mapping scalars of the same type
value	- Scalar	If to_replace is not a scalar, value must be None

Example Usage

>>> @bodo.jit
... def f(S, replace_dict):
...     return S.replace(replace_dict)
>>> S = pd.Series(pd.array([None, 1, None, -2, None, 5, None]))
>>> f(S, {1: -2, -2: 5, 5: 27})
0    <NA>
1      -2
2    <NA>
3       5
4    <NA>
5      27
6    <NA>
dtype: Int64

Reshaping, sorting