pd.timedelta_range

pandas.timedelta_range(start=None, end=None, periods=None, freq=None, name=None, closed=None)

Supported Arguments

argument	datatypes	other requirements
start	String or Timedelta
end	String or Timedelta
periods	Integer
freq	String	Must be a valid Pandas frequency
name	String
closed	String and one of ('left', 'right')

Note

• Exactly three of start, end, periods, and freq must be provided.
• This function is not parallelized yet.

Example Usage

>>> @bodo.jit
... def f():
...     return pd.timedelta_range(start="1 day", end="11 days 1 hour", periods=3)

>>> f()

TimedeltaIndex(['1 days 00:00:00', '6 days 00:30:00', '11 days 01:00:00'], dtype='timedelta64[ns]', freq=None)