pd.Series.nlargest¶ pandas.Series.nlargest(n=5, keep='first') Supported Arguments¶ argument datatypes n Integer Note Series type must be numeric Example Usage¶ >>> @bodo.jit ... def f(S): ... return S.nlargest(20) >>> S = pd.Series(np.arange(100)) % 7 >>> f(S) 20 6 27 6 41 6 34 6 55 6 13 6 83 6 90 6 6 6 69 6 48 6 76 6 62 6 97 6 19 5 5 5 26 5 61 5 12 5 68 5 dtype: int64