pd.Series.diff
pandas.Series.diff(periods=1)
Supported Arguments
| argument | datatypes | 
| periods | Integer | 
Note
Bodo only supports numeric and datetime64 types
 
Example Usage
>>> @bodo.jit
... def f(S):
...     return S.diff(3)
>>> S = pd.Series(np.arange(100)) % 7
>>> f(S)
0     NaN
1     NaN
2     NaN
3     3.0
4     3.0
     ...
95    3.0
96    3.0
97    3.0
98   -4.0
99   -4.0
Length: 100, dtype: float64