pd.Series.nlargest

pandas.Series.nlargest(n=5, keep='first')

Supported Arguments

argument	datatypes
n	Integer

Note

Series type must be numeric

Example Usage

>>> @bodo.jit
... def f(S):
...     return S.nlargest(20)
>>> S = pd.Series(np.arange(100)) % 7
>>> f(S)
20    6
27    6
41    6
34    6
55    6
13    6
83    6
90    6
6     6
69    6
48    6
76    6
62    6
97    6
19    5
5     5
26    5
61    5
12    5
68    5
dtype: int64